| X, Y, and Z |
Find the ordered triple (x,y,z) if x, y, and z are natural numbers which satisfy the following:
xyz=256
x + y + z = 41
x < y < z |
Problem Moderated by: Douglas |
| Problem Solution |
Since x,y,z divide 256=28, they are powers of 2 themselves.
since x+y+z is odd, x=20=1
inspection finds:
1 + 8 + 32 = 41
so (x,y,z) = (1,8,32)
Solution submitted by PdoX
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