Similar Triangles and Parallel Lines
Reference > Mathematics > Geometry > Similar TrianglesTake a look at the picture below:
In this picture, DE is parallel to BC. <ADE and <ABC are corresponding angles, which means they are congruent, and similarly, <AED and <ACB are corresponding angles, so they also are congruent.
Since the two triangles (ADE and ABC) have two pairs of congruent angles, this means that they are similar. That makes sense, doesn't it? Just by looking at them you should be able to see that theylook similar, and we just proved that they are!
So let's see what we can do with this information...
Problem #1: If AD = 5, DB = 5, and DE = 6, what is the length of BC?
Solution: AD / AB = DE / BC. This gives us 5/10 = 6/BC, from which we conclude that BC = 12.
Problem #2: AB = 16, BC = 12, DE = 9. What is the length of DB?
Solution: AD / AB = DE / BC, or AD / 16 = 9 / 12, from which AD = 12. And since DB = AB - AD, DB = 16 - 12 = 4.
Problem #3: The perimeter of ABC is 40, and the perimeter of ADE is 10. If BC = 10, what is the length of DE?
Solution: The perimeters of the triangles are in the same ratio as the sides, so 10 / 40 = x / 10, and x = 2.5
For the sample problems, use the diagram to the left.