Composite Functions and Function Values
Lesson Plans > Mathematics > Algebra > FunctionsComposite Functions and Function Values
When I explain functions to students, among all the information I give them about domain and ranges, I tell them: A function is simply a rule. You put a number in, the function performs some actions on that number according to the rule, and spits out a new number.
So if the function is f(x) = 3x + 2, the rule is "whatever number you put into the function, multiply it by three and add two."
f(1) means "the result when you put 1 into the function." Since the rule is "multiply by 3 and add two," the result can be shown like this:
f(x) = 3x + 2
f(1) = 3(1) + 2 = 3 + 2 = 5
I encourage my students to always write the rule again before performing operations on it. It helps them to visualize that whatever is in the parentheses replaces x in the rule.
We also look at things like f(k + 1). How do you evaluate that?
f(x) = 3x + 2
f(k + 1) = 3(k + 1) + 2 = 3k + 3 + 2 = 3k + 5
Doing several of these types of problems prepares students for composing functions:
If f(x) = 3x + 2 and g(x) = x2, what is f(g(x))?
Again, I encourage the students to write the rule out, and then write it with the replacement:
f(x) = 3x + 2
f(g(x)) = 3g(x) + 2
f(g(x)) = 3(x2) + 2 = 3x2 + 2
Then they do the reverse: g(f(x))
g(x) = x2
g(f(x)) = f(x)2 = (3x + 2)2 = 9x2 + 12x + 4
The following is a worksheet that gives each of the types of problems shown above.
Handouts/Worksheets
Function Worksheet
f(x) = 3x + 5 and g(x) = x2 + 2x, h(x) = x + 2, k(x) =- f(3) =
- f(-1) =
- g(0) =
- g(2) =
- f(4) + g(-2) =
- f(3m) =
- f(n - 2) =
- g(2k) =
- g(a + 2) =
- m(k4 - 5)
- k()1t + 1
- f(g(x)) =
- g(f(x)) =
- k(2) =
- k(0) =
- m(4) =
- m(2k - 2) =
- f(h(g(x)) =
- h(h(x)) =
- k(k(x)) =
- f(m(x)) =
- g(m(x)) - 2m(x) =
- m(g(x) - 4) =
- g(f(x) - h(x)) =